# Circular and Satellite Motion - Mission CG10 Detailed Help Two planets - planet A and planet B - are orbiting a star. If Planet A has an orbital radius which is two times (or three times) as large as Planet B, then the period of Planet A's orbit is ____ times larger than the period of Planet B's orbit. The Law of Harmonies: Kepler's law of harmonies proposed that the ratio of the square of the periods of any two planets is equal to the ratio of the cube of their average distances from the sun. This magical T2/R3 ratio shows very little variation from planet to planet. An extension of this law would be that the period of orbit must be greater for any planet which is a greater distance from the sun. More distant planets require greater periods of time to orbit than closer planets. Click the button below to play an audio file. Your browser does not support the audio element. Please download and view here. Applying Kepler's law of harmonies to this situation would result in:   TA2 / RA3 = TB2 / RB3 This equation can be algebraically rearranged to   TA2 / TB2 = RA3 / RB3 The ratio of the period squared of planet A to planet B will be equal to the ratio of the radius cubed of planet A to planet B. The ratio of the radii of the two planets is given - planet A's radius is four (or five) times larger than planet B's radius. The cube of this ratio is equal to the square of the ratio of the period. Taking the square root of the period squared ratio will yield the ratio of the periods of the planets. Mathematically, this could be written as   TA / TB = SQRT(TA2 / TB2) = SQRT(RA3 / RB3)  